10035 (1/5)
| #include <stdio.h> // carry: 5 + 4 = 9 -> not carry ; 5 + 5 = 10 -> carry (in decimal) int a, b; int carry[100]; int j = 0, k = 0; int l = 1000000000; int main(){ while(scanf("%d %d", &a, &b) != EOF ){ if(a == 0 && b == 0) break; carry[j] = 0; for(int i = 1; i < 11; i++){ if((int)(a / l) + (int)(b / l) >= 10){ carry[j]++; } a = a - (int)(a / l) * l; b = b - (int)(b / l) * l; l = l / 10; } l = 1000000000; j++; k++; } for(j = 0; j < k; j++){ if(carry[j] == 0){ printf("No carry operation.\n"); } else if(carry[j] == 1){ printf("1 carry operation.\n"); } else{ printf("%d carry operations.\n", carry[j]); } } return 0; } // DONE!!! |
494(2/5)
| #include <stdio.h> int main(){ char sen[10000]; int count, total; while(gets(sen)){ count = 0, total = 0; for(int i = 0; sen[i]; i++){ // sen[i] for the limit if( sen[i] >= 'a' && sen[i] <= 'z' || sen[i] >= 'A' && sen[i] <= 'Z'){ count = 1; } else{ total += count; count = 0; } } printf("%d\n", count + total); } return 0; } |
我發現超過10000系列的都比較直覺好懂
以下的像是494就是要知道說
在電腦判斷裡面可以用 該 字元 >= a 且 <= z 或 >= A 且 <= Z 來判斷
我一開始以為還要轉ASCII還是16進制= =
還好有爬文看一下
達人
